Volts to Watts Calculator
Power from V and A.
Open →Find the series resistor value for an LED.
| Power in resistor | — |
|---|---|
| Nearest E12 | — |
| Voltage across R | — |
| — |
An LED needs a series resistor to limit its current, or it burns out. The resistor drops the difference between the supply voltage and the LED’s forward voltage, at the desired current. Ohm’s law gives the value: R = (Vsupply − Vforward) ÷ current. Powering a 2 V LED at 20 mA from 12 V needs a 500 Ω resistor.
Also check the resistor’s power rating — the calculator shows the milliwatts it dissipates — and pick a standard (E12) value at or above the calculated resistance.
R = (supply voltage − LED forward voltage) ÷ current
R = (supply − LED forward voltage) ÷ current. A 2 V LED at 20 mA on 12 V needs about 500 Ω.
LEDs draw runaway current without one and quickly burn out. The resistor limits the current to a safe level.
Above the wattage it dissipates — shown here in milliwatts. A quarter-watt resistor covers most small LEDs.
Power from V and A.
Open →Appliance running cost.
Open →Divider output voltage.
Open →AWG for the load.
Open →Battery runtime.
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